statistics 2
Top of Form
Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. The table below gives the probability distribution for x, the number of children who inherit the disorder. Find the distribution’s mean and standard deviation.
Round your answers to one decimal place.
|
Probability Distribution |
||
|
x |
P(x) |
|
|
0 |
0.0 2 7 |
|
|
1 |
0.1 5 1 |
|
| 2 |
0. 3 22 |
|
| 3 | ||
|
4 |
||
| 5 |
The mean µ = .
The standard deviation σ = .
Question 3 of beta-blockers have been found to increase the likelihood of sleepwalking in cardiac patients. The table below contains the probability that x patients who were prescribed a certain type of beta blocker (out of a random sample of five) will report they have trouble with sleepwalking. Find the distribution’s mean and standard deviation. Round your answers to one decimal place.
Probability Distribution
x
P(x)
0
0.178
1
0.352
2
0.301
3
0.134
4
0.033
5
0.002
The mean µ = .
The standard deviation σ = .
Flag question: Question 4
Question 41 pts
The following table describes the results of roadworthiness tests of Ford Focus automobiles that are seven ore more years old (based on data from the U.S. Department of Transportation). The random variable x represents the number of cars that fail the roadworthiness test out of a random sample of six. Use the probability method to determine which values of x are significantly high. Assume the threshold for significance is 0.05. Enter your answer as an integer.
Probability Distribution
x
P(x)
0
0.377
1
0.399
2
0.176
3
0.041
4
0.005
5
0.000
6
0.000
Out of a random sample of six cars, or more failures would be a significantly high number.